spring 스프링

action-servlet.xml 설정

KIMSG 2017. 7. 22. 17:58
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns:context="http://www.springframework.org/schema/context"
    xmlns:p="http://www.springframework.org/schema/p"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xmlns="http://www.springframework.org/schema/beans"
    xmlns:mvc="http://www.springframework.org/schema/mvc"
    xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
       http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.0.xsd
       http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc.xsd">
 
    <context:component-scan base-package="com.today.maker"></context:component-scan>
    
    <mvc:interceptors>
        <mvc:interceptor>
            <mvc:mapping path="/**"/>
            <bean id="loggerInterceptor" class="com.today.maker.common.logger.LoggerInterceptor"></bean>
        </mvc:interceptor>
    </mvc:interceptors>
    
    <bean class="org.springframework.web.servlet.mvc.annotation.DefaultAnnotationHandlerMapping"/>
    
    <bean class="org.springframework.web.servlet.view.BeanNameViewResolver" p:order="0" />
    <bean id="jsonView" class="org.springframework.web.servlet.view.json.MappingJacksonJsonView" />   
    
    <bean
        class="org.springframework.web.servlet.view.UrlBasedViewResolver" p:order="1"
        p:viewClass="org.springframework.web.servlet.view.JstlView"
        p:prefix="/WEB-INF/jsp/" p:suffix=".jsp">
    </bean>
</beans>



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